Question

我试图执行一些东西,像facebookss 像部件,说的东西,比如:

You, Name1, Name2 and 20 other people like this

我收集了全部数据来显示这个 HTML, 但我似乎找不到合适的 algo 来组成 HTML 字符串。

我的主要问题是,我不知道何时要放 和 字符串或 、 (comma) 字符串。如果我只需要放名字, 它就会起作用, 但问题是, You 字符串总是必须先放。

我要在这里粘贴我的代码以及我为一些特殊病例得到的输出(这是PHP)

$current_user = 0;
$html = "";
$count = count($result);
$key = 0;
foreach($result as $liked){
    if($key + 1 > $limit)
        break;

    if($liked->uid == $user->uid){
        $current_user = 1;
        continue;
    }

    $html .= "<a href= ".$liked->href." >".$liked->name."</a>";

    if($key < $count - 2)
        $html .= ", ";
    elseif($key == $count - 2 && $key + 1 != $limit)
        $html .= " and ";

    $key++;
}

if($current_user){
    $userHtml = "You";

    if($count > 2)
        $userHtml .= ", ";
    elseif($count > 1)
        $userHtml .= " and ";

    $html = $userHtml.$html;
}

$html = "&hearts; by ".$html;

if($count > $limit){
    $difference = $count - $limit;
    $html .= " and ".$difference." ".format_plural($difference,"other","others");
}

return $html;

在特例中,当当前用户是最后一个喜欢这个的用户时, 它会显示:

♥ by You, admin, edu2004eu and

注意 < code> 和 < / code > 单词之后没有任何东西, 因为 < code> You 本来应该一直在它之后, 但我把它放在开头。有帮助吗? 我只需要逻辑, 而不是实际代码。

Answer 1

你可以尝试这样的东西:

$likedBy = array( admin ,  eduard ,  jeremy ,  someoneelse );

// check if I like it and if so move me to the front
if (in_array($currentUsername, $likedBy)) {
  $me = array_search($currentUsername, $likedBy);
  unset($likedBy[$me]);
  array_unshift($likedBy,  You );
}

// remove anything after the limit
$extra = array_splice($likedBy, 3);

// the comma list
$html = implode( ,  , $likedBy);

// any extras? if so, add them here, if not rewrite the list so
// it s "You, Eduard and admin"
if (!empty($extra)) {
  $html .=   and  .count($extra);
} else {
  $lastguy = array_splice($likedBy, 1);
  $html = implode( ,  , $likedBy).  and  .$lastguy;
}

$html .=   like this ;

Answer 2

Eduard, You can fix this simply by putting $key++; at the top of the loop and taking out all the places where you have $key + 1 in the loop.

我认为现在的情况是,$key+1 假设有一个当前用户。

如果当前用户不是在条目的第一个 $限制数中,此行也不会显示当前用户

if($key + 1 > $limit)
    break;

您可以在寻找当前用户的代码后放置此代码来修正此选项。

在爪哇(我知道,

    List<String> users = Arrays.asList("Brian","Tom","Jack","John");
    int key = 0;
    String html = "";
    String currentUser = "Brian";
    int limit = 3;
    boolean foundCurrentUser = false;
    for (String user : users) {
        key ++;
        if (currentUser == user) {
            foundCurrentUser = true;
            continue;
        }
        if (key > limit) {
            continue;
        }
        html += user;

        if (key < users.size() - 1) {
            html += ",";
        } else if (key == users.size() - 1 && key != limit) {
            html += " and ";
        }
    }
    if (foundCurrentUser) {
        String userHTML = "You";
        if (key > 2) {
            userHTML += ", ";
        } else if (key == 1) {
            userHTML += " and ";
        }
        html = userHTML + html;
    }

    html = "Likeed by " + html;
    if (users.size() > limit ) {
        html += " and 3 other people";
    }
    System.out.println(html);

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