即类似此代码的代码, 使打印输出未定义 。
int a=41; a++ & printf("%d
", a);
我不知道这次行动的确切名称
即类似此代码的代码, 使打印输出未定义 。
int a=41; a++ & printf("%d
", a);
我不知道这次行动的确切名称
问题在于它没有指定先评价哪个对象, printf
或 a/code >,并且由于一个对另一个具有副作用(您要么读
a
,然后写出来,然后再读出来,或者读起来,然后写出来),就会得到未定义的行为。
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