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这次行动有什么违法的?
原标题:What s so illegal about this operation

即类似此代码的代码, 使打印输出未定义 。

int a=41; a++ & printf("%d
", a);

我不知道这次行动的确切名称

最佳回答

问题在于它没有指定先评价哪个对象, printf a/code >,并且由于一个对另一个具有副作用(您要么读 a ,然后写出来,然后再读出来,或者读起来,然后写出来),就会得到未定义的行为。

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