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Mysql 查询 - 和条件一样计算
原标题:mysql query - counting like terms
  • 时间:2012-05-22 11:32:38
  •  标签:
  • mysql
  • sql

MySQL表格如下:

ID  term  timestamp

1   foo    xxxx
2   bar    xxxx
3   bar    xxxx
4   foo    xxxx
5   foo    xxxx
6   foo    xxxx
7   xxx    xxxx

我愿提出一份清单,按最常用术语的数量排列,列出该术语的最常用术语。

(e) 最终结果:

foo 
bar
xxx

但我不太清楚我在找什么, coUNT/Group BY等等。

最佳回答

下列 SQL 查询应该为您的问题提供一个解决方案 。

SELECT term
FROM tablename
GROUP BY term
ORDER BY COUNT(*) DESC
问题回答
SELECT COUNT(*), term FROM table GROUP BY term ORDER BY COUNT(*) DESC;

尝试

SELECT term, Count(*) AS cnt FROM mytable GROUP BY term ORDER BY cnt DESC

GROUP by 是正确无误的。 请试一下 :

SELECT term FROM table
GROUP BY term
ORDER BY COUNT(term) desc
SELECT TERM
FROM @table
GROUP BY TERM
HAVING COUNT(*) > 5 --replace with number you want
ORDER BY COUNT(*) 

此 SQL 查询应该做到这一点 :

SELECT term FROM my_table GROUP BY term ORDER BY COUNT(term) DESC;




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